Mathematics · Vectors
Let a vector αî + β&hat;j be obtained by rotating the vector √3î + &hat;j by an angle of 45° about the origin in the counterclockwise direction in the first quadrant. Then the area (in sq. units) of the triangle having vertices (α, β), (0, β) and (0, 0) is equal to:
- 11/2✓
- 21
- 31/√2
- 42√2
Correct answer
1/2
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