Mathematics · Trigonometry

Let 0° < θ < 90°. The expression (1 + cot2θ)(1 + tan2θ) × (sin θ - cosec θ)(cos θ - sec θ) is equal to:

Verified Solution4 OptionsUpdated: October 2026👁️1 View

1sec θ cosec θ✓
2sin θ + cos θ
3sin θ cos θ
4sec θ + cosec θ

Correct answer

sec θ cosec θ

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Let 0° < θ < 90°. The expression (1 + cot2θ)(1 + tan2θ) × (sin θ - cosec θ)(cos θ - sec θ) is equal to:

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Let 0° < θ < 90°. The expression (1 + cot2θ)(1 + tan2θ) × (sin θ - cosec θ)(cos θ - sec θ) is equal to:

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