Physics · Alternating Current

In a closed circuit, the current flowing through a 5 Ω resistor is I = 2 sin(300t) A. The value of voltage across it is ________.

Verified Solution4 OptionsUpdated: October 2026👁️1 View

1V = 40 sin(300t) V
2V = 30 sin(300t) V
3V = 20 sin(300t) V
4V = 10 sin(300t) V✓

Correct answer

V = 10 sin(300t) V

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In a closed circuit, the current flowing through a 5 Ω resistor is I = 2 sin(300t) A. The value of voltage across it is ________.

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In a closed circuit, the current flowing through a 5 Ω resistor is I = 2 sin(300t) A. The value of voltage across it is ________.

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