Mathematics · Trigonometry
If x = sin(2θ)cos(3θ) and y = sin(3θ)cos(2θ), then dydx =
- 13cos(3θ)cos(2θ) - 2sin(3θ)sin(2θ)2cos(2θ)cos(3θ) - 3sin(2θ)sin(3θ)✓
- 22cos(5θ) + cos(3θ)cos(2θ)2sin(5θ) - sin(3θ)cos(2θ)
- 32cos(5θ) - sin(3θ)sin(2θ)2cos(5θ) + cos(3θ)cos(2θ)
- 42cos(5θ) + sin(3θ)sin(2θ)2cos(5θ) - cos(3θ)cos(2θ)
Correct answer
3cos(3θ)cos(2θ) - 2sin(3θ)sin(2θ)2cos(2θ)cos(3θ) - 3sin(2θ)sin(3θ)
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