Physics · Superconductivity
If we apply a DC voltage V across a Josephson junction, the angular frequency ω of the AC Josephson current is given by:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 1ω = eV / ℏ
- 2ω = 2eV / ℏ✓
- 3ω = eV / 2h
- 4ω = 2V / eh
Correct answer
ω = 2eV / ℏ
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Start Free Mock Test →Preparing for Physics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Superconductivity MCQs →Want more practice questions on Superconductivity?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Physics · Superconductivity