Physics · Electromagnetic Waves
If the electric field intensity of a uniform plane electromagnetic wave is given as E = -301.6 sin(kz - ωt) ax + 452.4 sin(kz - ωt) ay V/m, then the magnetic intensity 'H' of this wave in A m-1 will be: [Given: Speed of light in vacuum c = 3 × 108 m/s, Permeability of vacuum μ0 = 4π × 10-7 N A-2]
- 1+0.8 sin(kz - ωt) ay + 0.8 sin(kz - ωt) ax
- 2+1.0 × 10-6 sin(kz - ωt) ay + 1.5 × 10-6 (kz - ωt) ax
- 3-0.8 sin(kz - ωt) ay - 1.2 sin(kz - ωt) ax✓
- 4-1.0 × 10-6 sin(kz - ωt) ay - 1.5 × 10-6 sin(kz - ωt) ax
Correct answer
-0.8 sin(kz - ωt) ay - 1.2 sin(kz - ωt) ax
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