Mathematics · Matrices and Determinants
If A = [cos(α) sin(α); -sin(α) cos(α)], then for any positive integer 'n', An is equal to:
- 1[cos((n+1)α) sin((n+1)α); -sin((n+1)α) cos((n+1)α)]
- 2[cos(nα) sin(nα); -sin(nα) cos(nα)]✓
- 3[cosn+1(α) sinn+1(α); -sinn+1(α) cosn+1(α)]
- 4[cosn(α) sinn(α); -sinn(α) cosn(α)]
Correct answer
[cos(nα) sin(nα); -sin(nα) cos(nα)]
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