Mathematics · Definite Integrals

If ∫0π (sin3x) e-sin2x dx = α - βe ∫01 √t et dt, then α + β is equal to:

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If ∫0π (sin3x) e-sin2x dx = α - βe ∫01 √t et dt, then α + β is equal to:

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If ∫0π (sin3x) e-sin2x dx = α - βe ∫01 √t et dt, then α + β is equal to:

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