Physics · Gravitation
Considering Earth to be a uniform sphere of radius R and uniform density ρ, the value of acceleration due to gravity g on its surface in terms of R, ρ, and G is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1g = GMρR2
- 2g = 43πρGR✓
- 3g = √ 43πρGR
- 4g = 3πRρG
Correct answer
g = 43πρGR
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