Physics · Nuclear Physics
An unstable isotope 40K19 decays by β+-decay as follows: 40K19 → 40Ar18 + β+ + νe Given that the atomic masses are m(40K) = 39.96399 u and m(40Ar) = 39.962384 u, and the mass of an electron/positron is me = 0.0005486 u, what is the approximate Q-value of this decay?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 12.012 MeV
- 21.501 MeV
- 30.985 MeV
- 40.474 MeV✓
Correct answer
0.474 MeV
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