Physics · Rotational Motion
A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω. Two particles, each of mass m, are gently attached at diametrically opposite points of the ring. The new angular speed of the ring becomes:
- 1ωMM + m
- 2ωM + 2mM
- 3ωMM + 2m✓
- 4ωM - 2mM + 2m
Correct answer
ωMM + 2m
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