Physics · Center of Mass
A rod of length L has non-uniform linear mass density given by ρ(x) = a + b(x/L)2, where a and b are constants and 0 ≤ x ≤ L. The value of x for the center of mass of the rod is at:
- 12(3a + b)3(2a + b) L
- 24(2a + b)3(3a + b) L
- 33(3a + b)4(2a + b) L✓
- 43(2a + b)4(3a + b) L
Correct answer
3(3a + b)4(2a + b) L
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