Mathematics · Dynamics of Machinery
A machine is coupled to a two-stroke engine which produces a torque of T = 800 + 180 sin(3θ) N·m, where θ is the crank angle. If the mean engine speed is 600 rpm, what will be the power developed by the engine? [Take π = 3.14]
- 130.62 kW
- 260.17 kW
- 350.24 kW✓
- 425.12 kW
Correct answer
50.24 kW
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